json - 如何在 Javascript/Typescript 中移除在另一个对象中存在的对象属性

我有这个对象：

{
  "id": "33343232",
  "createdAt": "2022-07-26T13:44:01.080Z",
  "updatedAt": "2022-07-26T13:45:31.000Z",
  "name": "Name Here",
  "description": "text",
}

另一个对象是：

specificFeatures": {
    "id": "33343232",
    "createdAt": "2022-07-26T13:44:01.087Z",
    "updatedAt": "2022-07-26T13:45:31.000Z",
    "name": "Name Here",
    "description": "text",
    "coverage": "international",
    "income": 0,
    "observationIncome": "",
}

现在，我想要删除 specificFeatures 对象中与第一个对象相同的属性键。

在这个例子中，它将是：

specificFeatures": {
    "coverage": "international",
    "income": 0,
    "observationIncome": "",
}

你能告诉我我该怎么做吗？

答案＃1

为了实现这一点，你可以简单地遍历对象属性，检查“original”对象是否具有该属性，如果有，则从“specificFeatures”对象中删除它：

const original = {
  "id": "33343232",
  "createdAt": "2022-07-26T13:44:01.080Z",
  "updatedAt": "2022-07-26T13:45:31.000Z",
  "name": "Name Here",
  "description": "text",
}

const specificFeatures = {
  "id": "33343232",
  "createdAt": "2022-07-26T13:44:01.087Z",
  "updatedAt": "2022-07-26T13:45:31.000Z",
  "name": "Name Here",
  "description": "text",
  "coverage": "international",
  "income": 0,
  "observationIncome": "",
}

// Iterate over object keys
Object.keys(specificFeatures).forEach(prop => {
  // Check if the "original" object has the property defined
  if (original.hasOwnProperty(prop)) {
    // Delete the property from the "specificFeatures" object
    delete specificFeatures[prop];
  }
});

console.log(specificFeatures);

注意，这种方式会修改原始对象，如果你需要保持原始对象不变，则应创建一个新的唯一副本。可能的解决方案之一是结合使用 Object.entries() 和 Array.reduce() 方法：

const original = {
  "id": "33343232",
  "createdAt": "2022-07-26T13:44:01.080Z",
  "updatedAt": "2022-07-26T13:45:31.000Z",
  "name": "Name Here",
  "description": "text",
}

const specificFeatures = {
  "id": "33343232",
  "createdAt": "2022-07-26T13:44:01.087Z",
  "updatedAt": "2022-07-26T13:45:31.000Z",
  "name": "Name Here",
  "description": "text",
  "coverage": "international",
  "income": 0,
  "observationIncome": "",
}

const result = Object.entries(specificFeatures).reduce((acc, [key, val]) => {
  if (!original.hasOwnProperty(key))
    acc[key] = val;
  return acc;
}, {});

console.log(result);
console.log('Is a different object:', result !== specificFeatures);

答案＃2

这可以通过一个简单的一行代码实现：

var specificFeatures = {
  "id": "33343232",
  "createdAt": "2022-07-26T13:44:01.087Z",
  "updatedAt": "2022-07-26T13:45:31.000Z",
  "name": "Name Here",
  "description": "text",
  "coverage": "international",
  "income": 0,
  "observationIncome": "",
}

var myObj = {
  "id": "33343232",
  "createdAt": "2022-07-26T13:44:01.080Z",
  "updatedAt": "2022-07-26T13:45:31.000Z",
  "name": "Name Here",
  "description": "text",
}

const newObj = Object.fromEntries(Object.entries(specificFeatures).filter(([key]) => !(myObj.hasOwnProperty(key))));
console.log(newObj);

上述操作将对象转换为条目数组，然后在转换回对象之前根据 myObj 筛选键。